FREE PDF ORACLE - 1Z0-071 - NEWEST VALID TEST ORACLE DATABASE SQL TIPS

Free PDF Oracle - 1z0-071 - Newest Valid Test Oracle Database SQL Tips

Free PDF Oracle - 1z0-071 - Newest Valid Test Oracle Database SQL Tips

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Oracle 1z1-071 exam is a certification exam designed to test the skills and knowledge of individuals in the area of Oracle Database SQL. 1z0-071 Exam is intended for individuals who work with databases and need to demonstrate their proficiency in SQL programming language. 1z0-071 exam is a requirement for those seeking to become Oracle Certified Associates in Oracle Database 12c or 11g.

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Target Audience

The Oracle 1z0-071 Exam is designed for those professionals who have some level of experience in operating with Oracle SQL and PL/SQL technologies and want to improve their expertise to perform the job roles of a Database Administrator or a Developer.

Oracle Database SQL Sample Questions (Q263-Q268):

NEW QUESTION # 263
View the Exhibit and examine the description of the ORDERS table.

  • A. WHERE order_date > TO_DATE('JUL 10 2006','MON DD YYYY')
  • B. 2003','MON DD YYYY') )
    WHERE order_date > TO_CHAR(ADD_MONTHS(SYSDATE,6),'MON DD YYYY')
  • C. WHERE TO_CHAR(order_date,'MON DD YYYY') = 'JAN 20 2003'
  • D. Which two WHERE clause conditions demonstrate the correct usage of conversion functions? (Choose two.) WHERE order_date_IN ( TO_DATE('OCT 21 2003','MON DD YYYY'), TO_CHAR('NOV 21

Answer: A,C


NEW QUESTION # 264
Examine the description of the BRICKS table;

Examine the description of the BRICKS_STAGE table;

Which two queries execute successfully?

  • A. SELECT shape,color,weight from bricks
    MINUS
    SELECT * FROM bricks_stage;
  • B. SELECT shape,color FROM bricks
    MINUS
    SELECT color,shape FROM bricks_stage;
  • C. SELECT brick_id,shape FROM bricks
    MINUS
    SELECT WEIGHT,COLOR from bricks_stage;
  • D. select * from bricks
    MINUS
    select * from bricks_stage;
  • E. SELECT shape,color FROM bricks
    MINUS
    SELECT WEIGHT,color FROM bricks_stage;

Answer: B,C


NEW QUESTION # 265
Which two are true about external tables that use the ORACLE _DATAPUMP access driver?

  • A. Creating an external table creates a dump file that can be used only by an external table in the same database.
  • B. Creating an external table creates a dump file that can be used by an external table in the same or a different database.
  • C. Creating an external table creates a directory object.
  • D. When creating an external table, data can be selected only from a table whose rows are stored in database blocks.
  • E. When creating an external table, data can be selected from another external table or from a table whose rows are stored in database blocks.

Answer: E

Explanation:
External tables using the ORACLE_DATAPUMP access driver have specific characteristics:
C). Creating an external table using the ORACLE_DATAPUMP access driver allows you to select data from other tables, including another external table or a regular table whose rows are stored in database blocks.
A, B, D, and E are incorrect. Specifically:
* A is incorrect because creating an external table does not automatically create a directory object; the
* directory object must exist prior to or be created separately.
* B is incorrect as it limits the creation to tables stored in database blocks, which is not a restriction.
* D is incorrect because creating an external table does not create a dump file; it reads from an existing dump file created by Data Pump.
* E is also incorrect because the dump file is not created as part of the external table creation process.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "CREATE TABLE" for External Tables


NEW QUESTION # 266
View the Exhibit and examine the structure of the ORDERStable.

Which UPDATEstatement is valid?
UPDATE orders

  • A. SET order_date = '12-mar-2007',
    order_total IS NULL
    WHERE order_id = 2455;
    UPDATE orders
  • B. SET order_date = TO_DATE('12-mar-2007','dd-mon-yyyy'),
    SET order_total = TO_NUMBER (NULL)
    WHERE order_id = 2455;
  • C. SET order_date = '12-mar-2007',
    AND order_total = TO_NUMBER(NULL)
    WHERE order_id = 2455;
    UPDATE orders
  • D. SET order_date = '12-mar-2007',
    order_total = NULL
    WHERE order_id = 2455;
    UPDATE orders

Answer: D


NEW QUESTION # 267
View the Exhibit and examine the structure of the ORDER_ITEMS table.

You must select the ORDER_ID of the order that has the highest total value among all the orders in the ORDER_ITEMS table.
Which query would produce the desired result?

  • A. SELECT order_id
    FROM order_items
    WHERE(unit_price*quantity) = MAX(unit_price*quantity)
    GROUP BY order_id);
  • B. SELECT order_id
    FROM order_items
    WHERE (unit_price*quantity) = (SELECT MAX(unit_price*quantity)
    FROM order_items
    GROUP BY order_id)
  • C. SELECT order_id
    FROM order_items
    WHERE(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity)
    FROM order_items) GROUP BY order_id);
  • D. SELECT order_id
    FROM order_items
    GROUP BY order_id
    HAVING SUM(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity)) FROM order_items GROUP BY order_id);

Answer: D


NEW QUESTION # 268
......

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